Question

what is the common difference of an AP T27-T23=64

Answer 1

Let a is the first term and d is the common difference of the AP

Given T27 - T23 = 64

=> {a + (27 - 1)d} - {a + (23 - 1)d} = 64 {since Tn = a + (n - 1)d}

=> (a + 26d) - (a + 22d) = 64

=> a + 26d - a - 22d = 64

=> 4d = 64

=> d = 64/4

=> d = 16

So, the common difference of AP is 16
Hope it Helps you!

Answer 2

a-- first term

 T27 - T23 = 64

Tn = a + (n - 1)d

{a + (27 - 1)d} - {a + (23 - 1)d} = 64    

 (a + 26d) - (a + 22d) = 64

 a + 26d - a - 22d = 64

 4d = 64

 d = 64/4

So, the common difference of AP is 16

hope it helps!!!