Question

What is the common difference of the arithmetic sequence 13, 19, 25, 31 ... A. -6 B.-5 C. 2 D.6

Answer 1

Common Difference is 6

Step-by-step explanation:

Let the First term be $T_1 = 13$

Second Term be $T_2 = 19$

Third Term be $T_3 = 25$

and Fourth term be $T_4 = 31$

we know that Common Difference = Final Term - Initial Term

So, Applying this relationship -

Common Difference, $T_2 - T_1 = 19 - 13 = 6$

Similarly, $T_3 - T_2 = 25 - 19 = 6$

Also, $T_4 - T_3 = 31 - 25 = 6$

Since the Common Difference is 6, same for all conditions, the Sequence represents Arithmetic Progression.