Question

WHAT IS THE COMPLETE FORMULA FOR Є0U[MIU]0?

Answer 1

Answer:

In electromagnetism, permeability is the measure of the resistance of a material against the formation of a magnetic field, otherwise known as distributed inductance in transmission line theory. Hence, it is the degree of magnetization that a material obtains in response to an applied magnetic field. Magnetic permeability is typically represented by the (italicized) Greek letter μ. The term was coined in September 1885 by Oliver Heaviside. The reciprocal of magnetic permeability is magnetic reluctivity.

In SI units, permeability is measured in henries per meter (H/m), or equivalently in newtons per ampere squared (N⋅A−2). The permeability constant μ0, also known as the magnetic constant or the permeability of free space, is a measure of the amount of resistance encountered when forming a magnetic field in a classical vacuum. Until 20 May 2019, the magnetic constant had the exact (defined)[1] value μ0 = 4π × 10−7 H/m ≈ 12.57×10−7 H/m.

On 20 May 2019, a revision to the SI system went into effect, making the vacuum permeability no longer a constant but rather a value that needs to be determined experimentally;[2] 4π × 1.00000000082(20)×10−7 H⋅m−1 is a recently measured value in the new system. It is proportional to the dimensionless fine-structure constant with no other dependencies.[3][4]

A closely related property of materials is magnetic susceptibility, which is a dimensionless proportionality factor that indicates the degree of magnetization of a material in response to an applied magnetic field.

Answer 2

Answer:

The conical Frustum formulas in terms of r and h is as follows: Volume of a conical frustum = V = (1/3) * π * h * (r12 + r22 + (r1 * r2)).In geometry, a frustum (plural: frusta or frustums) is the portion of a solid (normally a cone or pyramid) that lies between one or two parallel planes cutting it. A right frustum is a parallel truncation of a right pyramid or right cone.Hey Dear,

◆ Answer -

F = mv^2/r

◆ Explaination -

First, we'll write down known dimensions of given quantities.

[F] = [L1M1T-2]

[v] = [L1T-1]

[m] = [M]

[r] = [L]

Let x, y & z are numbers such that F = k.v^x.m^y.r^z

In dimensional form, this can be written as -

[F] = [v]^x.[m]^y. [r]^z

[L1M1T-2] = [L1T-1]^x.[M]^y.[L]^z

[L1M1T-2] = [L^(x+z).M^(y).T^(-x)

Comparing indexes on both sides -

x + z = 1

y = 1

-x = -2

Solving these equations,

x = 2

y = 1

z = -1

Hence,

F = k.ν^x.m^y.r^z

F = k × v^2 × m^1 × r^-1

F = k.v^2.m/r

F = mv^2/r ...(k=1)

Thus, centripetal force of the particle in UCM is mv^2/r.