Question

What is the complete ionic equation for the reaction 2KOH(aq)+H2SO4(aq)→2H2O(l)+K2SO4(aq)?

Answer 1

To find the complete ionic equation:

Consider:

Equation for the dissociation of the strong base in aqueous solution:

KOH  (aq)------> K⁺(aq) + OH⁻(aq)

Equation for the dissociation of the strong acid in aqueous solution:

H₂SO₄(aq)------>2H⁺(aq) + SO₄²⁻(aq)

On the product' side, potassium sulfate that is a ionic compound:

K₂SO₄(aq)------>2K⁺  +SO₄²⁻  

Water, a covalent compound:

So net balanced equation will be:

K⁺(aq) + OH⁻(aq) +2H⁺(aq) + SO₄²⁻(aq)------>2K⁺  + SO₄²⁻  +H₂O(l)

Net ionic equation by eliminating the spectator ions:

OH⁻(aq) +2H⁺(aq)-------->H₂O(l)

Answer 2

Answer:

OH⁻(aq) +2H⁺(aq) --> H₂O(l)

Explanation:

Apex