Question

What is the completely factored form of p4 – 16?
A)p – 2)(p – 2)(p + 2)(p + 2)
B)(p – 2)(p – 2)(p – 2)(p – 2)
C)(p minus 2) (p + 2) (p squared + 2 p + 4)
D)(p minus 2) (p + 2) (p squared + 4)

Answer 1

Answer:

Step-by-step explanation:

its too easy Q

Answer 2

The required option is D).  

Step-by-step explanation:

We have,

$p^4-16$

To find, the factorisation of $p^4-16=?$

∴ $p^4-16$

= $(p^2)^2-(2^2)^2$

Using the algebraic identity,

$a^2-b^2=(a+b)(a-b)$

$=(p^2+2^2)(p^2-2^2)$

Again, using the algebraic identity,

$a^2-b^2=(a+b)(a-b)$

$=(p^2+4)(p+2)(p-2)$

∴ The factorisation of $p^4-16$ $=(p^2+4)(p+2)(p-2)$

Thus, the required option is D).