Question

What is the completely factored form of x2 – 16xy + 64y2? xy(x – 16 + 64y) xy(x + 16 + 64y) (x – 8y)(x – 8y) (x + 8y)(x + 8y)

Answer 1

Answer:

(x-8y)(x-8y)

Explanation:

x²-16xy+64y²

= x² - 2*x*8y +(8y)²

= (x-8y)²

= (x-8y)(x-8y)

••••

Answer 2

Answer: (x-8y)(x-8y)

Step-by-step explanation:

To find: The factor of $x^2-16xy +64y^2$

$x^2-16xy +64y^2\\\\ (x)^2 - 2\times x\times 8y +(8y)^2\\\\ \text {As we know } \\\\a^2-2ab+b^2 = (a-b)^2\\\\ (x)^2 - 2\times x\times 8y +(8y)^2 = (x-8y)^2\\\\ (x-8y)(x-8y)$

Hence, the completely factor is (x-8y)(x-8y)