Question

What is the component of a=-4i^+3j^ along b=-2i^+5j^

Answer 1

Answer:

Component of A along B is 3.944

Explanation:

A = 4i + 3j

B = 2i + 5j

find the magnitude of A and B

$|A| = \sqrt{4^2+3^2} =\sqrt{20} =2\sqrt{5}$

$|B| = \sqrt{3^2+5^2} =\sqrt{34}$

Component of A along B is

A · B = |A||B| cosθ

|A| cosθ = [ A · B ] / |B|

= [ 8 + 15 ] / $\sqrt{34}$

= 23/ $\sqrt{34}$

= 3.944

Component of A along B is 3.944