Math, asked by aryandhavale, 3 months ago

what is the compound interest on Rs. 200 for 1 year at 10% rate compounded half - yearly​

Answers

Answered by shalinithore100
5

Step-by-step explanation:

Here, Principal P = Rs. 1000

R =10% per annum and n=2 years

∴ Amount after 2 years = P (1+

200

R

)

2n

= Rs. 1000×(1+

200

10

)

2×2

=Rs.1000×(1+

20

1

)

4

=Rs.1000×(

20

21

)

4

= Rs.1000×

20

21

×

20

21

×

20

21

×

20

21

=Rs.1215.50

Hence, compound interest = Amount - Principal

=Rs.1215.50−Rs.1000=Rs.215.50

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Answered by RvChaudharY50
32

Given :-

  • Principal = Rs.200
  • Time = 1 year.
  • Rate = 10% compounded half-yearly .

To Find :-

  • Compound interest = ?

Solution :-

we know that, when rate is compounded half - yearly,

  • Time = 2 times = 1 * 2 = 2 years.
  • Rate = Half = 10 / 2 = 5% per annum .
  • Amount = P[1 + (R/100)]^(time)
  • CI = Amount - Principal .

putting values we get,

→ A = 200[1 + (5/100)]²

→ A = 200 * [1 + (1/20)]²

→ A = 200 * (21/20)²

→ A = (200 * 441)/400

→ A = (441/2)

→ A = Rs.220.5 .

therefore,

→ CI = A - P

→ CI = 220.5 - 200

→ CI = Rs.20.5 (Ans.)

Hence, Amount after 1 year is Rs.220.5 and compound interest recieved is Rs.20.5 .

Learn more :-

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