what is the concentration in in moles of sodium hydroxide per dm3 of solution Contains 120g of sodium hydroxide in 100cm3 of solution.{H=1, O=16, Na=23} .
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Answer:
Given, Mass of NaOH in 100 ml of soln = 120 g
No. Of moles of Na in 100 ml soln = GM/MM
=120/40 = 3
No. Of moles in 1 dm³ soln = 30
(1 dm³ = 1 L)
Hence the molarity becomes 30 M
Or you can use Molarity = 1000×GM÷MM× volume(in ml)
Note:- GM => Given mass
MM => molar mass
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