Chemistry, asked by vrafael053, 3 months ago

What is the concentration, in ppm, if 0.808 grams of CaCl2 is dissolved in 250.0 ml of water.

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Answered by XxZeeshanarshiALLHA

3

Answer:

0.808 grams of CaCl2 is dissolved in 250.0 ml of water. 0.808 g x 1000 = 808 mg. 250 ml/1000 = 0.25 L. 808 mg/0.25 L= 3232 mg/L = ppm.

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