Question

what is the concentration of a NaOH if 25.0 mL are required to react with 0.500 grams of KHP (MM= 204.23 g/mole)?

Answer 1

Answer:

I Hope it's helpfull

Explanation:

C6H4

(CO−2K+)

(CO2H

, KHP

+NaOH

C6H4(CO−2K+)

(CO−2Na+)

+H2O

Moles of KHP

=0.6939g

204.22g

mol−1=3.398×10−3

mol

26.55

mL

=3.398×10−3

mol

26.55

mL×10−3

L

mL−1=0.1280

molL−1