What is the concentration of a solution of cane sugar which is isotonic with a solution containing 9 gm of urea?
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Osmotic pressure of isotonic solution is same.
It means the concentration of both the solution is same.
Concentration of urea solution = moles of urea L-1.
Moles of urea = Given mass /molar mass of urea
= 8.6 g /60 g mol-1
= 8.6/60 mole
Concentration of urea solution = 8.6/60 mol/L..........(1)
Concentration of unknown solution = moles of unknown solute L-1
Moles of unknown solute = given mass /molar mass of unknown(m)
5 % means 5 g per 100 ml = 50 g per 1000 ml or 50 g/ L
Moles of unknown solute = (50 / m) mol
Concentration of unknown solution = (50 / m) mol/L...........(2)
As mentioned above the concentration of both the solution is same So, eq (1) = eq. (2)
That is , 8.6/60 mol/L = (50 / m) mol/L
m = 50 x 60 /8.6 = 348.9 g mol-1
It means the concentration of both the solution is same.
Concentration of urea solution = moles of urea L-1.
Moles of urea = Given mass /molar mass of urea
= 8.6 g /60 g mol-1
= 8.6/60 mole
Concentration of urea solution = 8.6/60 mol/L..........(1)
Concentration of unknown solution = moles of unknown solute L-1
Moles of unknown solute = given mass /molar mass of unknown(m)
5 % means 5 g per 100 ml = 50 g per 1000 ml or 50 g/ L
Moles of unknown solute = (50 / m) mol
Concentration of unknown solution = (50 / m) mol/L...........(2)
As mentioned above the concentration of both the solution is same So, eq (1) = eq. (2)
That is , 8.6/60 mol/L = (50 / m) mol/L
m = 50 x 60 /8.6 = 348.9 g mol-1
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