Question

What is the concentration of dissolved oxygen at 50°C under
pressure of one atmosphere if partial pressure of oxygen at
50°C is 0.14 atm.​

Answer 1

Answer:

Partial pressure = Mole fraction × Total Pressure

Pt= 1atm

Xo2 = 0.14

Xo2 = nO2/nO2 + nH2O

nO2 + 55.5/nO2 = 1/0.14

1 + 55.5/nO2 = 7.14

55.5/nO2 = 6.14

nO2 - 9

Molarity= 9/1= 9M

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Answer 2

0.00527 mole/litre is the concentration of oxygen at partial pressure of 0.14 atm at 50 degrees.

Explanation:

We will use the formula of Gas Law

PV=nRT

OR

P/RT=n/V

here partial pressure of oxygen is given as 0.14 atm

Temperature = 323.15 Kelvin

R= 0.0821L atm/ mol.K

n/V= O.14/ 0.0821*323.15

     = 0.00527 mole/litre

Since n/V is the concentration as moles per litre the concentration of the oxygen gas is 0.00527 mole/litre.

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