Question

What is the concentration of nacl, in mol dm3, when 10.0 cm3 of 0.200 mol dm3 nacl solution is added to 30.0 cm3 of 0.600 mol dm3 nacl solution?

Answer 1

Given:

the concentration of NaCl - M₁ = 0.2mol dm³

Volume - V₁ = 10cm³

Concentration of NaCl solution added = 0.6 mol dm³

Volume - V₂ = 30cm³

To Find: The concentration of mixed NaCl solution -M =?

Solution:

Formula used:

• M₁V₁ = M₂V₂
• MV = M₁V₁ + M₂V₂

Total volume of the mixed solution formed - V = V₁ + V₂

                                                                             = 10 + 30

                                                                             = 40 cm³

Applying the above formula:

MV = M₁V₁ + M₂V₂

M × 40 = 0.2 × 10 + 0.6 × 30

M × 40 = 2 + 18

M = 20/40

M = 1/2

M = 0.5 mol dm³

Hence, the concentration of NaCl solution formed = 0.5 mol dm³.