Question

what is the concentration of salt solution if 12 gram of potassium chloride is made to form 132 ml of solution​

Answer 1

Answer:

In order to find the molarity of the solution, you must determine the number of moles of solute present in exactly

   1 L=103 mL

of solution. Notice that you already know the number of milligrams of sodium chloride, the solute, present in 4 mL of solution, so start by calculating the mass of solute present in 103 mL of solution.

   103mL solution

⋅240 mg NaCl4mL solution

   =60⋅103 mg

Since

   1 g=103.mg

you can say that 103 mL of solution contain

   60⋅103.mg=60.g

of sodium chloride. Now, to convert this to moles, use the molar mass of the compound

   60g

⋅1 mole NaCl58.44g

   =1.027 moles NaCl

Since this represents the number of moles of sodium chloride present in 103 mL of solution, you can say that the molarity of the solution is equal to

   molarity = 1 mol L−1

Explanation:

Answer 2

Explanation:

In order to find the molarity of the solution, you must determine the number of moles of solute present in exactly

  1 L=103 mL

of solution. Notice that you already know the number of milligrams of sodium chloride, the solute, present in 4 mL of solution, so start by calculating the mass of solute present in 103 mL of solution.

  103mL solution

⋅240 mg NaCl4mL solution

  =60⋅103 mg

Since

  1 g=103.mg

you can say that 103 mL of solution contain

  60⋅103.mg=60.g

of sodium chloride. Now, to convert this to moles, use the molar mass of the compound

  60g

⋅1 mole NaCl58.44g

  =1.027 moles NaCl

Since this represents the number of moles of sodium chloride present in 103 mL of solution, you can say that the molarity of the solution is equal to

  molarity = 1 mol L−1

Explanation: