Question

What is the concentration of the barium hydroxide solution if 50.0 mL of a 0.425 M HNO3 solution is required to neutralize a 36.8 mL sample?

0.156 M

0.289 M

0.577 M

Answer 1

Answer:0.289 M

Explanation:

Answer 2

Answer:

Option 3 : 0.577 M

Explanation:

Let us first write the chemical equation for this reaction:

BaOH(aq)+HN03(aq)→BaNO3(aq)+H2O(l)

Using the molarity equation, let us find the moles of HNO3 first:

Molarity = mol solute / L

mol solute=(molarity)(L soln)

mol HNO3= 0.425 x 0.050

= 0.02125mol of HNO3

Now consider the chemical reaction, we find that same number of moles of BaNO3 are required

0.02125 mol of BaN03

Now again we use the molarity solution formula;

molarity= mol soluteL soln

M = 0.02125/ 0.0368lL= 0.577 M