Question

What is the condition for maximum range of projectile ?

Answer 1

Answer:

The object should be projected at an angle 45° with the horizontal for the maximum range

Answer 2

CONDITION FOR MAX RANGE IF PROJECTILE:

• Let's assume that projectile has been launched with a velocity u and at an angle of $\theta$ such that it achieved the maximum height of H and range of R.

Now, general expression for range of a projectile is:

$\boxed{R = \dfrac{ {u}^{2} \sin(2 \theta) }{g} }$

• So, maximum value of range, the value of $\sin(2\theta)$ also has to be maximum.

$\implies \: \sin(2 \theta) = 1$

$\implies \: 2 \theta = {90}^{ \circ}$

$\implies \: \theta = {45}^{ \circ}$

So, projectile has to be thrown at an angle of 45° for max range .