What is the conjugate base of [Al (H2O)3 (OH)3]- ?
Give the reason behind it.
Answers
Answered by
0
Answer:
As we know that bases are OH^-1 Donor.
So, the conjugate base of [Al(H2O3)3(OH)3]^-1 is
[Al(H2O3)3(OH)3] .
[Al(H2O3)3(OH)3]^-1 --> [AL(H2O3)3(OH)3] + OH^-1
Answered by
1
Conjugate base of [Al (H2O)3 (OH)3]-
Explanation:
When proton is lost then conjugate base is formed from an acidic solution.
In the given solution conjugate base will be
Al(H2O)2(OH)4]−
This is formed because one OH- ion added in the place of H+ ion.
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