What is the constant ratio between the consective term of 5,-25,125,-625
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Step-by-step explanation:
first term a=5
second term ar=25=5×5
common ratio r=5
let nth term = 5^10=5×5⁹
5×5⁹=ar^(n-1)
5×5⁹=5×5^(n-1)
5⁹=5^(n-1)
n=10
therefore 10th term of the GP is 5^10
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