what is the converse of Pythagoras theorem
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☜☆☞The converse of the Pythagoras Theorem states that if the sum of the square of the two sides of a triangle is equal to the square of the third side then it is called as a right angle triangle .☜☆☞
nivedhini2004:
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The converse of the Pythagorean Theorem is:
If the square of the length of the longest side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is a right triangle.
That is, in ΔABC, if c2=a2+b2 then ∠C is a right triangle, ΔPQR being the right angle.
We can prove this by contradiction.
Let us assume that c2=a2+b2 in ΔABC and the triangle is not a right triangle.
Now consider another triangle ΔPQR. We construct ΔPQR so that PR=a, QR=b and ∠R is a right angle.
By the Pythagorean Theorem, (PQ)2=a2+b2.
But we know that a2+b2=c2 and a2+b2=c2 and c=AB.
So, (PQ)2=a2+b2=(AB)2.
That is, (PQ)2=(AB)2.
Since PQ and AB are lengths of sides, we can take positive square roots.
PQ=AB
That is, all the three sides of ΔPQR are congruent to the three sides of ΔABC. So, the two triangles are congruent by the Side-Side-Side Congruence Property.
Since ΔABC is congruent to ΔPQR and ΔPQR is a right triangle, ΔABC must also be a right triangle.
This is a contradiction. Therefore, our assumption must be wrong.
#BeBrainly
If the square of the length of the longest side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is a right triangle.
That is, in ΔABC, if c2=a2+b2 then ∠C is a right triangle, ΔPQR being the right angle.
We can prove this by contradiction.
Let us assume that c2=a2+b2 in ΔABC and the triangle is not a right triangle.
Now consider another triangle ΔPQR. We construct ΔPQR so that PR=a, QR=b and ∠R is a right angle.
By the Pythagorean Theorem, (PQ)2=a2+b2.
But we know that a2+b2=c2 and a2+b2=c2 and c=AB.
So, (PQ)2=a2+b2=(AB)2.
That is, (PQ)2=(AB)2.
Since PQ and AB are lengths of sides, we can take positive square roots.
PQ=AB
That is, all the three sides of ΔPQR are congruent to the three sides of ΔABC. So, the two triangles are congruent by the Side-Side-Side Congruence Property.
Since ΔABC is congruent to ΔPQR and ΔPQR is a right triangle, ΔABC must also be a right triangle.
This is a contradiction. Therefore, our assumption must be wrong.
#BeBrainly
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