Question

what is the coordination number of sodium in sodium oxide

Answer 1

The coordination number of Na in Na2O is 4. Na+ ion is surrounded by four oxide ions and O2- ion is surrounded by eight Na+ ions hence the coordination number of Na in Na2O is 4.

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Answer 2

ANSWER:

The "coordination number" of sodium in sodium oxide is 4.

EXPLANATION:

    The "coordination number" of Na in $\mathrm{Na}_{2} \mathrm{O}$ is 4. $\mathrm{Na}^{+}$ ion is surrounded by four oxide ions and $\mathrm{O}^{2-}$ion is surrounded by eight$\mathrm{Na}^{+}$ ions. Hence the "coordination number" of Na in $\mathrm{Na}_{2} \mathrm{O}$ is 4.

   So the coordination number of oxide ion in sodium oxide is eight and the coordination number of sodium ion in sodium oxide is 4.