what is the correct area of this figure
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join BD
we get 2 triangles ABD and BCD
area of triangle = half base × hight
area of triangle ABD = 1/2 ×40 ×9
=180 sq cm
area of triangle BCD = 1/2 × 15 × 28
=210 sq cm
area of quadrilateral ABCD = area of triangle ABD + area of triangle BCD
= 180 +210
= 390
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