Question

What is the correct order of bond order of Cl-O bond ? Ans is ClO4-> ClO3-> ClO2-> ClO- Please explain this

Answer 1

we know that bond order inversely proportional of bond length.

here
we can find its bond order by its resonating structure .

also we can see that ClO4- maximum resonating structure so its bond order maximum .

Answer 2

The correct bond order of Cl-O bond is $ClO_4^-> ClO_3^-> ClO_2^-> ClO^-$.

Explanation:

• To calculate the bond order of  of oxide based acid radicals, the following formula must be used:

Bond order = Valency of the peripheral atom + $\frac{Charge on Acid Radical}{Total number of peripheral atoms}$

• Using this formula, the bond order value for given oxide based acid radicals must be calculated.
• Accordingly the bond order value for given ions are as follows:

1. $ClO_4^-$

Bond order = Valency of the peripheral atom + $\frac{Charge on Acid Radical}{Total number of peripheral atoms}$

Bond order = 2 + $\frac{-1}{4}$

Bond order = 2 + (-0.25)

Bond order = 2 - 0.25

Bond order of $ClO_4^-$ = 1.75

2. $ClO_3^-$

Bond order = Valency of the peripheral atom + $\frac{Charge on Acid Radical}{Total number of peripheral atoms}$

Bond order = 2 + $\frac{-1}{3}$

Bond order = 2 + (-0.33)

Bond order = 2 - 0.33

Bond order of $ClO_3^-$ = 1.66

3. $ClO_2^-$

Bond order = Valency of the peripheral atom + $\frac{Charge on Acid Radical}{Total number of peripheral atoms}$

Bond order = 2 + $\frac{-1}{2}$

Bond order = 2 + (-0.5)

Bond order = 2 - 0.5

Bond order of $ClO_2^-$ = 1.5

4. $ClO^-$

Bond order = Valency of the peripheral atom + $\frac{Charge on Acid Radical}{Total number of peripheral atoms}$

Bond order = 2 + $\frac{-1}{1}$

Bond order = 2 + (-1)

Bond order = 2 - 1

Bond order of $ClO^-$ = 1

• From the above calculation it is inferred that the correct order of bond order of Cl-O bond in decreasing order is

$ClO_4^-> ClO_3^-> ClO_2^-> ClO^-$

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