Chemistry, asked by Hrishabh8948, 10 months ago

What is the correct order of decreasing stability of the
following cations?

I. CH₃ - CH - CH₃

II. CH₃ - CH - OCH₃

III. CH₃ - CH - CH₂ - OCH₃

(a) II > I > III (b) II > III > I
(c) III > I > II (d) I > II > III

Answers

Answered by Anonymous
4

Answer:

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Answered by brokendreams
1

II > I > III is the trend of stability of the carbocations.

Explanation:

  • Carbocations are the positively charged carbon atoms that are usually reaction intermediates and they are very short lived.
  • The carboncation are itself not very stable, and don't usually form without any supporting effect.
  • The carbocations are stabilised by the Resonance, inductive, hyper conjunction and different effects.
  • In the 1st carbocation, this is stabilised by the weak inductive effects of the two methyl groups.
  • In the 2nd carbocation, this is stabilised by the strong resonance of the methoxy group.
  • In the 3rd carboncation, this is distabilised by the strong negative inductive effects of the methoxy group.
  • So the stability trend is II > I > III.

For more information about carbocation,

https://brainly.in/question/7425761

what is carbocation ? - Brainly.in

https://brainly.in/question/8838752

the decreasing order of stability of following cations is

ethane carbocation

ethene carbocation

ethyne carbocation

ch3-c+≈o

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