Chemistry, asked by ilayacheliyan7469, 11 months ago

What is the correct order of reactivity of alcohols in the
following reaction?
R —OH + HCl □(→┴ZnCl₂ ) R – Cl + H₂O
(a) 1° > 2° > 3° (b) 1° < 2° < 3°
(c) 3° > 2° > 1° (d) 3° > 1° > 2°

Answers

Answered by Fatimakincsem
11

The correct order of reactivity is  3∘>2∘>1∘

Option (c) is correct.

Explanation:

  • Reagent mixture of concentrated HCl and dry anhydrous ZnCl2 is called Lucas reagent.
  • This reaction is known as Lucas test.
  • In this reaction, the carbocation is formed as an intermediate.
  • The formation of carbocation determines the rate of the reaction as the reaction is a slow step of the mechanism.
  • the order of reactivity is tertiary alcohol>secondary alcohol by SN 1 mechanism.
  • With Lucas reagent, tertiary alcohol reacts fastest.

The correct order of reactivity of alcohols in the following reaction is:

R−OH+HCl   →  (ZnCl2)  R−Cl+ H2O

3∘ > 2∘ > 1∘

Thus the correct order of reactivity is 3 ∘ > 2 ∘ > 1 ∘

Also learn more

Explain the gradation in reactivity of halogen family?

https://brainly.in/question/4591359

Answered by muskanjangde861
1

Explanation:

option c is the correct option

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