What is the correct order of reactivity of alcohols in the
following reaction?
R —OH + HCl □(→┴ZnCl₂ ) R – Cl + H₂O
(a) 1° > 2° > 3° (b) 1° < 2° < 3°
(c) 3° > 2° > 1° (d) 3° > 1° > 2°
Answers
Answered by
11
The correct order of reactivity is 3∘>2∘>1∘
Option (c) is correct.
Explanation:
- Reagent mixture of concentrated HCl and dry anhydrous ZnCl2 is called Lucas reagent.
- This reaction is known as Lucas test.
- In this reaction, the carbocation is formed as an intermediate.
- The formation of carbocation determines the rate of the reaction as the reaction is a slow step of the mechanism.
- the order of reactivity is tertiary alcohol>secondary alcohol by SN 1 mechanism.
- With Lucas reagent, tertiary alcohol reacts fastest.
The correct order of reactivity of alcohols in the following reaction is:
R−OH+HCl → (ZnCl2) R−Cl+ H2O
3∘ > 2∘ > 1∘
Thus the correct order of reactivity is 3 ∘ > 2 ∘ > 1 ∘
Also learn more
Explain the gradation in reactivity of halogen family?
https://brainly.in/question/4591359
Answered by
1
Explanation:
option c is the correct option
Similar questions