What is the correct PH and POH values of aqueous solutions at 25Degree centi grade?
Answers
Answered by
0
6
p
H
=5
⇒[H
+
]=10
−5
⇒
c×K
a
=10
−5
⇒10
−2
×K
a
=10
−10
⇒K
a
=10
−8
K
a
of BOH=K
a
of HA=10
−8
∴α for BOH=
C
1
K
a
=
10
−4
10
−8
=0.01α0.1
Now [OH
−
]=cα
=10
−4
×10
−2
=10
−6
∴pOH=6
Similar questions