Question

what is the covalency and oxidation state of nitrogen in NO2 and N2O4??

Answer 1

Hello friend!!!

Here's the answer to your question.

Let us take oxidation state of N in NO2 is x

so
x + (-2)×2 = 0 (because the compound is neutral)
x = +4

So the oxidation number of N in NO2 is +4 and covalency is also +4

Let us consider the oxidation state of N in N2O4 is y

So
2y + (-2)×4 = 0
2y = 8
y= +4

So oxidation state of N in N2O4 is +4 and covalency is also +4.

HOPE THAT HELPS.... ☺️

Answer 2

Answer:

x+x+(-2) ×4=0

2x=8

x=8/2

x=+4