What is the critical angle of a transparent crystal is 45 degree then its?
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When light is travelling from a denser medium to a rarer medium and the angle of incident is equal to the critical angle, the angle of refraction is 90o.90o.
⇒sinicrsin90o=1μ,⇒sinicrsin90o=1μ, where icricr is the critical angle and μμ is the refractive index of the crystal with respect to air.
⇒μ=1sinicr=1sin45o=2–√.⇒μ=1sinicr=1sin45o=2.
According to Brewster’s law, the tangent of the polarising angle is equal to the refractive index of the refracting medium at which partial reflection takes place.
⇒tanip=μ,⇒tanip=μ, where ipip is the polarising angle.
⇒ip=arctanμ=arctan2–√=54.74o.⇒ip=arctanμ=arctan2=54.74o.
⇒⇒ The polarising angle is 54.74o.54.74o.
⇒sinicrsin90o=1μ,⇒sinicrsin90o=1μ, where icricr is the critical angle and μμ is the refractive index of the crystal with respect to air.
⇒μ=1sinicr=1sin45o=2–√.⇒μ=1sinicr=1sin45o=2.
According to Brewster’s law, the tangent of the polarising angle is equal to the refractive index of the refracting medium at which partial reflection takes place.
⇒tanip=μ,⇒tanip=μ, where ipip is the polarising angle.
⇒ip=arctanμ=arctan2–√=54.74o.⇒ip=arctanμ=arctan2=54.74o.
⇒⇒ The polarising angle is 54.74o.54.74o.
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