Math, asked by vishnuvardhan42009, 6 months ago

what is the critical angle of benzene at 42 degrees

Answers

Answered by muskan0000017
2

Let the critical angle be C and refractive index be μ. According to Snell's Law, C=sin −1 ( μ1 )⟹42 ∘ =sin −1 ( μ1 )⟹sin(42 ∘ ) μ= 0.671=1.49is the required refractive index of benzene.

Answered by Anonymous
8

Answer:

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According to Snell's Law, C=sin −1 ( μ1 )⟹42 ∘ =sin −1 ( μ1 )⟹sin(42 ∘ ) μ= 0.671=1.49is the required refractive index of benzene.

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