Question

What is the critical angle of the light on the interface when its polarizing angle at the
interface is 53°?
(a) 38.9°
(b) 48.90
(c) 39.89
(d) 49.80​

Answer 1

Given - Polarising angle - 53°

Find - Critical angle of light

Solution - To find critical angle with respect to polarising angle, following formula will be used -

sin theta(c) = 1/tan theta(p)

In the equation, theta(c) stands for critical angle and theta(p) stands for polarising angle.

Keeping the values in equation-

sin theta(c) = 1/tan 53°

sin theta(c) = 1/ 1.32

sin theta(c) = 0.75

theta(c) = 48.59

Hence, critical angle will be 48.59°