Question

What is the critical depth of vertical
cut in a saturated cohesive soil with
c=15.5 kN/m2 and y = 18 kN/m3 ?​

Answer 1

The depth is 1.72 meter.

Step-by-step explanation:

We are given the following in the question:

c = 15.5 kN/m2

$\gamma = 18 ~kN/m3$

We have to find the critical depth of vertical  cut in a saturated cohesive soil.

The depth is given by formula:

$d = \dfrac{2c}{\gamma \sqrt{K_A}}$

Since $K_A = 1$ for $\phi_c = 0$.

Thus, putting values, we get,

$d = \dfrac{2\times 15.5}{18} = 1.72~m$

Thus, the depth is 1.72 meter.

#LearnMore

A cut of depth 12m is made in a cohesive soil deposit ( c = 40 kn/m , ϕ=0 and γ = 20 kn/m ). If the required factor of safety is 2.0, the stability number is

https://brainly.in/question/8114475

Answer 2

Step-by-step explanation:

given :-

c = 15.5 KN/m2

y = 18 KN/m2

formula used for critical depth

h= 4c/y[tan(45+∆\2)]

for cohesive soil ∆=0

h = 4x15.5/18

h= 3.44m