Question

What is the critical length (in mm) for a glass cube having density 2025 Kg/m3 to float on a fluid having surface tension 25 mN/m? Neglect the buoyancy force acting on block (Take g = 9.8 m/s2​

Answer 1

Answer:

2.01$\times 10^{-6}$

Explanation:

The critical length, or lc, for analogue transmissions is specified as being equal to one-fourth of the wavelength of the highest signal frequency present in the signal.

Critical length:

$l_c=\frac{\lambda_m}{4}=\frac{1}{4 t_{p d} f_m}$=$\frac{1}{2025 \times 25 \times 9.8}$=2.01$\times 10^{-6}$

The quickest rise time (or fall time) of a signal pulse is one of the most crucial characteristics in the case of digital signals since it indicates when one logic level changes to another, or when the data bit transitions. The critical length (lc) of a digital signal is the distance along which the signal propagates with a delay equal to half the quickest rise time of the signal pulses.

The critical length (lc) of a digital signal is the distance along which the signal propagates with a delay equal to half the quickest rise time of the signal pulses. The signal's propagation time across the length lc is given by tpd.lc = tr/2 if tr = the digital signal's fastest rising time (by definition of lc).

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