Question

What is the cross sectional area of a circular ring of d = 38 mm d= 32 mm​

Answer 1

Cross-sectional area of a circular ring is given by the formula,

$A = \pi (R^{2} - r^{2})$,

where, R is the outer radius and r is the inner radius.

Here, R = 38mm and r = 32mm

So, A = 3.14 ($38^{2} - 32^{2}$)

A = 3.14 × (1444 - 1024)

A = 3.14 × 420

A = 1318.8 $mm^{2}$

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