what is the cross sectional area of a circular ring of D 38 millimetre and 32 millimetre
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Step-by-step explanation:
The area of a circle is square of it's radius multiplied by 22/7.
The area of this ring will be difference between the area of a circle with diameter of 38mm (radius 19mm) and area of a circle with diameter of 32mm (radius 16mm).
(19*19*22/7) - (16*16*22*7) = 1134.57 - 804.57 = 330
So the area of one side of this ring will be 330 sq.mm.
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