Question

What is the cube of 74088 by prime factorisation method

Answer 1

Prime factorization of 74088
=2 x 2 x 2 x 3 x 3 x 3 x 7 x 7 x 7
=2³ x 3³ x 7³

So, cuberoot of 74088
=2x3x7
=42

and cube of 74088
$= 2^{9} * 3^{9} * 7^{9}$
=406671383849472

Answer 2

PRIME FACTORISATION OF 74088
$74088 = 2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 7 \times 7 \times 7 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 7 \times 7 \times 7 \\ cube \: root \: of74088 \: is \\42 \\ and \: cube \: of \: 74088 \\ 2 {9}^{9} \times 3 {}^{9} \times 7 {}^{9} \\ 4066713838494172$
I hope this helps you!
Vaibhav