Question

what is the cube root of every odd number??​

Answer 1

Step-by-step explanation:

Cube root of every odd number is always odd.

Answer 2

Answer:

The cube root of zero is zero. Every non-zero real number has 3 cube roots, two of which are complex and one of which is real. It does not matter whether the number is even or odd, integer or non-integer.

But since you specifically asked for odd numbers, here are some examples:

1–√3=1 , reason: 13=1 .

27−−√3=3 , reason: 33=27 .

125−−−√3=5 , reason: 53=125 .

343−−−√3=7 , reason: 73=343 .

−1−−−√3=−1 , reason: (−1)3=−1 .

−27−−−−√3=−3 , reason: (−3)3=−27 .

−125−−−−√3=−5 , reason: (−5)3=−125 .

−343−−−−√3=−7 , reason: (−7)3=−343 .

If an odd integer is not a perfect cube, then its cube root is irrational and so can only be represented approximately as a decimal.

For example:

3–√3≈1.44224957030740838232163831078

5–√3≈1.70997594667669698935310887254