Question

what is the current flowing through an iron of 1500 w when connected to 200 volt source​

Answer 1

Answer:

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Explanation:

Power =P=VI⟹1000=250I⟹I=2501000=4A

∴(i) Electric current flowing through heater=I=4A

∴(ii) Resistance of heated wire R=IV=4250=62.5Ω

∴(iii) Thermal energy produced per minute by heater=ET=P×1min=1000×60sec=60000J

∴(iv) Electrical energy spent in kilowatt-hour by heater in 2 hours=1000PKW×2hour=2KW-hour

Answer 2

Answer:

Power =P=VI⟹1000=250I⟹I=

250

1000

=4A

∴(i) Electric current flowing through heater=I=4A

∴(ii) Resistance of heated wire R=

I

V

=

4

250

=62.5Ω

∴(iii) Thermal energy produced per minute by heater=E

T

=P×1min=1000×60sec=60000J

∴(iv) Electrical energy spent in kilowatt-hour by heater in 2 hours=

1000

P

KW×2hour=2KW-hour