what is the current flowing through the 3Ohm resistor?
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10 ampere
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Answer:
Here you can clearly see that 6Ω and 3Ω resistors are in parallel resistance.
Equivalent resistance between them=(R1R2/R1+R2)
=(6×3/6+3)Ω
=18/9Ω
=2Ω
The 10Ω resistor and 2Ω resistors are in series resultant.
Equivalent resistance between them=(R1+R2)Ω
=(10+2)Ω
=12Ω
Let the rule of ohm's law,
V=12 Volt,I=?,R=12Ω
V=IR
or, 12=i×12
Finally, I=1A
The current flowing through the 3ohm resistor is 1A.
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