what is the current if 4 ohm and 2 ohm resisters are connected in series and 6V potential difference is applied?
Answers
Answered by
0
Answer:
total resistance R = 4 + 2 = 6 ohm
potential difference V = 6V
so current I = V/R = 6/6 = 1 A
Answered by
0
Answer: 1 A
Explanation:
V=IR
total resistance in series = R1 + R2 = 4 + 2 = 6 ohm
V= 6V
therefore, 6= I x 6
I = 6/6 = 1
so, I = 1 amp
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