Question

What is the current if 4 ohm and 2ohm resistor are connected in series and 6v potential difference is applied

Answer 1

current = 1 A

Explanation:

Data:

resistor (R1) = 4ohm

resistor (R2) = 2ohm

voltage (V) = 6V

current (I) = ?

Solution:

current remains same in series and sivides in parallel combinations.So,

V = IReq ( equivalent resistance)

V = I ( R1+R2)

V = I ( 4+2)

6 = I(6)

6 /6 = I

I = 1 A

NOW,

V1 = IR1 V2 = IR2

V2 = 1×2

V1 = 1×4 V2 = 2V

V1 = 4V

HOPE IT HELPS....

Answer 2

Answer:-

• R1=4ohm
• R2=2ohm

Finding Equivalent Resistance:-

$\boxed{\sf R=R_1+R_2}$

$\\ \qquad\sf\longmapsto R=4+2$

$\\ \qquad\sf\longmapsto R=6\Omega$

• Potential difference=V=6V
• Current=I=?

According to ohms law

$\boxed{\sf \dfrac{V}{I}=R}$

$\\ \qquad\sf\longmapsto I=\dfrac{V}{R}$

$\\ \qquad\sf\longmapsto I=\dfrac{6}{6}$

$\\ \qquad\sf\longmapsto I=1A$