Question

What is the current if 4ohm and 2ohm resistors are connected in series and 6volt potential difference is applied?

Answer 1

Given :

• First Resistance (R1) = 4 ohm
• Second resistance (R2) = 2 ohm
• Potential Difference (V) = 6 V

To Find :

• Current flowing in circuit

Solution :

We are given that there are two resistances of 4 ohm and 2 ohm, they are connected in series to a 6 Volt battery.

So, The equivalent resistance in circuit is :

⇒Rs = R1 + R2 + ........ + Rn

⇒Rs = R1 + R2

⇒Rs = 4 + 2

➠Rs = 6

Equivalent resistance is 6 ohms

__________________________

For calculating current in circuit, Use Ohm's Law :

⇒V = IR

⇒V = I * Rs

⇒I = Rs/V

⇒I = 6/6

⇒I = 1

➠ Current flowing in circuit is 1 Ampere

Answer 2

Answer :

Given that 4Ω and 2Ω resistors are connected in series and 6volt potential difference is is applied.

We have to find current flowing in circuit.

Here as we know the formula for finding equivalent resistance in series :

R(Series) = R₁ + R₂ + R₃ + ...........

So equivalent resistance :

→ R(Series) = 4 + 2

→ R(Series) = 6Ω

Now we have,potential difference(v) = 6v

We will use Ohm's law :

→ V = IR

Where,

• V : Potential difference
• I : Current
• R : Resistance

Substituting values,

→ 6 = I × 6

→ 6 = 6I

→ I = 6/6

→ I = 1 A

Current flowing in circuit = 1 Amphere. ✓