Question

what is the current in a wire loop of resistance 10 ohm which the magnetic flux changes from zero to 10 wb in 1seconds

Answer 1

Answer:

1 A

Explanation:

use Faraday's law

put emf = iR

Answer 2

Answer:

The value of current in the wire loop is equal to one ampere.

Explanation:

Given:

The resistance in the wire $R=10$Ω

Change in magnetic flux, $d\phi=10-0=10Wb$

and in time $dt=1sec$

We know  $emf=\frac{d\phi}{dt}$

$emf=\frac{10}{1} =10Wbs^{-1}$

$emf=10V$

Now current in wire loop,  $I=\frac{emf}{R}$                         ............(1)

Put the values of emf and R in eq.(1),

∴   $I=\frac{10V}{10ohm} =1A$

Therefore the current in the wire loop will be 1A.