Question

what is the current in the circuit shown in fig ​

Answer 1

Answer:

R= 4×2/(4+2)

R=8/6=4/3

I=V/R=2×3/4=1.5 Ampere

Answer 2

1/Rp = 1/4 + 1/2

Rp = 4/3

v = iR(by ohms law)

i = 2v*3/4 = 3/2 = 1.5A

Since resistance are in parallel and proportional by 2:1

so current flowing in 2ohm resistor is 1/2 A

and in two 2 ohm resistor is 1A