Question

what is the current intensity of a circuit with a resistor of 1.5 ohm and a potential difference of 5.8 volt​

Answer 1

Answer:

v =ir

v given as 5.8 volts

r given as 1.5 ohms

then

according to the formula

5.8 = i * 1.5

so

i = 5.8/1.5

i=3.866 amperes

Answer 2

Explanation:

current, I =V/R=5.8/1.5=3.866ampere