Question

what is the current through each of the resistance in the following circuit
​

Answer 1

Answer:

Due to balanced wheatstone bridge ABCEA BE=8Ω can be taken out.

R

AC

=

(1+2)+(2+4)

(1+2)(2+4)

=

9

18

=2

Now, ACFGHA is a balanced Wheatstone bridge, hence HC=10Ω can be taken out.

R

AG

=

6+18

6∗18

=

24

108

=4.5Ω

R

total

=2+4.5=6.5

Hence, current i=

R

total

V

=

6.5

6.5

=1A

Answer 2

Answer:

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