Question

what is the curved surface area of a right circular cone whose hight is 10 and radius is 24​

Answer 1

Answer:

Step-by-step explanation:

slant height ²=radius²+height²

                    =24²+ 10²

                    =576+100

slant height =√676=26

curved surface area of a right circular cone=πrl

                                                                       =3.14×24×26

                                                                       =1959.36 unit²

Answer 2

Step-by-step explanation:

CSA of the cone =

$\pi \: r \: l$

Radius = 24 height =10 Slant height (l) = ?

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: slant \: height = \sqrt{r { }^{2} } + {h}^{2}$

=

=√576 +100= √676

=√676

=26

CSA of the cone = 22/7×24 ×26

=1961.14