Question

What is the curved surface area of cone if slant height is 41 cm and radius of the base is 9 cm.(take pi=3.14) *

1166.66 sq.cm

1156.66 sq.cm

1158.66 sq.cm

None of these​

Answer 1

Given:

• Slant Height = 41 cm
• Radius of base = 9 cm

To find:

Curved Surface area of cone = ?

Solution:

Here, for finding the Curved Surface area of cone, apply the below mentioned formula.

CSA of cone = πrl

where

• r is the radius
• l is the slant Height

Substitute the given values in the formula.

CSA = 3.14 × 9 × 41

→ CSA = 3.14 × 369

→ CSA = 1158.66 cm²

KNOW MORE:

• Volume of cone = ⅓ πr²h
• Slant Height of cone = √(r² + h²)
• TSA of cone = πr (l + r)

Answer 2

✬ The curved surface area of cone is option c)1158.66 sq cm✬

Step-by-step explanation:

Given: Slant height(l) of cone is 41 cm and radius of the base(r) is 9 cm.

To find: Curved surface area of cone

Required Formula:

• Curved surface area(CSA) of cone = πrl

Solution:

$\\ :\implies\sf{CSA_{(cone)}= 3.14\times \times 9 \times 41 }\\ \\ :\implies\sf{CSA_{(cone)} = 28.26 \times 41} \\ \\ :\implies \underline{ \boxed{\mathfrak{CSA_{(cone)} = 1158.66 \: sq.cm}}} \pink{ \bigstar}$

• Hence,The curved surface area of cone is option c)1158.66 sq cm