Question

What is the cutoff frequency of a dielectric rectangular waveguide?

Answer 1

Héy buddy.!!

So, Thé ÃnSwer is --) Signals can progress along awaveguide using a number of modes. However the dominant mode is the one that has the lowest cutoff frequency. For a rectangular waveguide, this is the TE10 mode. The TE means transverse electric and indicates that the electric field is transverse to the direction of propagation.

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Answer 2

The cutoff frequencies of a rectangular waveguide depend on the dimensions, and the permittivity of the dielectric material inside the waveguide.

Let’s take the fundamental mode as an example (TE10), after solving Helmholtz equation, and applying the boundary conditions we can find that the cutoff frequency is given by

fc = Kc. C / 2π√ epsylin r


From the previous equation we can see that by using a a higher permittivity material, the cutoff frequency decreases.

where the cutoff wave number is constant for each waveguide, and is given by

Kc = π/a



where a is the longest side along the x- axis.