Question

What is the cylindrical materials wire where whose 1.0 length has a resistance of 2.0 ohm? the diameter of the wire is 0.5m

Answer 1

Answer:

Explanation:

Given: Length = 1.0 m.

R = 2.0 Ohms.

Dia. = 5*10^-4 m. r = 2.5*10^-4 m.

A = pi*r^2 = 3.14 * 6.25*10^-8 = 1.863*10^-7 m^2.

R = P*L/A.

2 = P*1.0/1.86*10^-7,

2 = 5.37*10^6P,

P = 3.72*10^-7 Ohm-meters.