What is the cylindrical materials wire where whose 1.0 length has a resistance of 2.0 ohm? the diameter of the wire is 0.5m
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Answer:
Explanation:
Given: Length = 1.0 m.
R = 2.0 Ohms.
Dia. = 5*10^-4 m. r = 2.5*10^-4 m.
A = pi*r^2 = 3.14 * 6.25*10^-8 = 1.863*10^-7 m^2.
R = P*L/A.
2 = P*1.0/1.86*10^-7,
2 = 5.37*10^6P,
P = 3.72*10^-7 Ohm-meters.
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