what is the day on 23 june 1977 with full explanation
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This is the question from Calendar topic in reasoning.
Note:
Here are the following codes, u should remember:
Jan and October = 0.
May = 1
August = 2
Feb/March/Nov = 3
June = 4
Sept/Dec = 5
July/April = 6.
Now, Here comes the Day of the week related to odd days:
Sun = 0
Mon = 1
Tue = 1
Wed = 2
Thur = 4
Fri = 5
Sat = 6.
Now,
On moving to ur question.
Given 23rd June 1977.
In 1977, Divide 77/4 = 19.
Code for June = 4.
Mentioned Date = 23.
Result = 77 + 19 + 4 + 23
= 123.
To find the day of the week, divide the result by 7 and write the remainder = 123/7
= 4.
4 is the code for Thursday.
Therefore the day is Thursday.
Hope this helps!
Note:
Here are the following codes, u should remember:
Jan and October = 0.
May = 1
August = 2
Feb/March/Nov = 3
June = 4
Sept/Dec = 5
July/April = 6.
Now, Here comes the Day of the week related to odd days:
Sun = 0
Mon = 1
Tue = 1
Wed = 2
Thur = 4
Fri = 5
Sat = 6.
Now,
On moving to ur question.
Given 23rd June 1977.
In 1977, Divide 77/4 = 19.
Code for June = 4.
Mentioned Date = 23.
Result = 77 + 19 + 4 + 23
= 123.
To find the day of the week, divide the result by 7 and write the remainder = 123/7
= 4.
4 is the code for Thursday.
Therefore the day is Thursday.
Hope this helps!
Anonymous:
Outstanding answer ! Superb ! KEEP IT UP BHAI
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